1.

What will be the output of the following pseudo-code when parameters are passed by reference and dynamic scoping is assumed?a=3;void n(x) {x = x * a; print (x) ; }void m(y) {a = 1; a = y - a; n (a); print (a) ; }void main() { m(a); }

A. 6, 2
B. 6, 6
C. 4, 2
D. 4, 4
Answer» E.


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