What will be output of the following code?

public class Boxer1

{

Integer i;

int x;

public Boxer1(int y)

{

x = i+y;

System.out.println(x);

}

public static void main(String[] args)

{

new Boxer1 (new Integer(4));

}

}

Question

What will be output of the following code?

    public class Boxer1 

    {

        Integer i;

        int x;

       public Boxer1(int y) 

       {

            x = i+y;

            System.out.println(x);

       }

       public static void main(String[] args) 

       {

           new Boxer1 (new Integer(4));

       }

    }

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

The value “4” is printed at the command line

TuteeHUB · Answer

Compilation fails because of an error in line

TuteeHUB · Answer

A NullPointerException occurs at runtime

TuteeHUB · Answer

An IllegalStateException occurs at runtime

1.	What will be output of the following code? public class Boxer1 { Integer i; int x; public Boxer1(int y) { x = i+y; System.out.println(x); } public static void main(String[] args) { new Boxer1 (new Integer(4)); } }
A.	The value “4” is printed at the command line
B.	Compilation fails because of an error in line
C.	A NullPointerException occurs at runtime
D.	An IllegalStateException occurs at runtime
Answer» E.

What will be output of the following code? public class Boxer1 { Integer i; int x; public Boxer1(int y) { x = i+y; System.out.println(x); } public static void main(String[] args) { new Boxer1 (new Integer(4)); } }

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