What is the sum of the series 0.3 + 0.33 + 0.333 + …n terms?

Question

TuteeHUB · Accepted Answer

$\frac{1}{3}\left[ {{\rm{n}} - \frac{2}{9}\left( {1 - \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]$

TuteeHUB · Answer

$\frac{1}{3}\left[ {{\rm{n}} - \frac{1}{9}\left( {1 - \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]$

TuteeHUB · Answer

$\frac{1}{3}\left[ {{\rm{n}} - \frac{1}{3}\left( {1 - \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]$

TuteeHUB · Answer

$\frac{1}{3}\left[ {{\rm{n}} - \frac{1}{9}\left( {1 + \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]$

1.	What is the sum of the series 0.3 + 0.33 + 0.333 + …n terms?
A.	\(\frac{1}{3}\left[ {{\rm{n}} - \frac{1}{9}\left( {1 - \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]\)
B.	\(\frac{1}{3}\left[ {{\rm{n}} - \frac{2}{9}\left( {1 - \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]\)
C.	\(\frac{1}{3}\left[ {{\rm{n}} - \frac{1}{3}\left( {1 - \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]\)
D.	\(\frac{1}{3}\left[ {{\rm{n}} - \frac{1}{9}\left( {1 + \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]\)
Answer» B. \(\frac{1}{3}\left[ {{\rm{n}} - \frac{2}{9}\left( {1 - \frac{1}{{{{10}^{\rm{n}}}}}} \right)} \right]\)

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