1.

What is the simplified value of (x128 + 1)(x32 + 1)(x64 + 1)(x16 + 1)(x8 + 1)(x4 + 1)(x2 + 1)(x + 1)?

A. x256– 1
B. (x128 – 1)/(x – 1)
C. (x64 – 1)/(x – 1)
D. (x256 – 1)/(x – 1)
Answer» E.


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