What is the probability that a non-leap year contains 53 Saturdays?

1.	What is the probability that a non-leap year contains 53 Saturdays?
A.	\[\frac{2}{7}\]
B.	\[\frac{1}{7}\]
C.	\[\frac{2}{365}\]
D.	\[\frac{1}{365}\]
Answer» C. \[\frac{2}{365}\]

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What is the probability that a non-leap year contains 53 Saturdays?

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