1.

What is the force required to be exerted by the punch in order to shear out the blank (for a circular disc) of 20 mm diameter and 1.5 mm thickness and having a shear strength equal to 300 MPa?

A. 9.0 kN              
B. 18.0 kN
C. 28.3 kN            
D. 45.0 kN
Answer» D. 45.0 kN


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