What is the equation of the hyperbola having latus rectum and eccentricity 8 and $\frac{3}{{\sqrt 5 }}$ respectively?

Question

What is the equation of the hyperbola having latus rectum and eccentricity 8 and $\frac{3}{{\sqrt 5 }}$ respectively?

TuteeHUB · Accepted Answer

$\frac{{{x^2}}}{{40}} - \frac{{{y^2}}}{{20}} = 1$

TuteeHUB · Answer

$\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{20}} = 1$

TuteeHUB · Answer

$\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{30}} = 1$

TuteeHUB · Answer

$\frac{{{x^2}}}{{30}} - \frac{{{y^2}}}{{25}} = 1$

1.	What is the equation of the hyperbola having latus rectum and eccentricity 8 and \(\frac{3}{{\sqrt 5 }}\) respectively?
A.	\(\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{20}} = 1\)
B.	\(\frac{{{x^2}}}{{40}} - \frac{{{y^2}}}{{20}} = 1\)
C.	\(\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{30}} = 1\)
D.	\(\frac{{{x^2}}}{{30}} - \frac{{{y^2}}}{{25}} = 1\)
Answer» B. \(\frac{{{x^2}}}{{40}} - \frac{{{y^2}}}{{20}} = 1\)

What is the equation of the hyperbola having latus rectum and eccentricity 8 and \(\frac{3}{{\sqrt 5 }}\) respectively?