1.

What is the area of an isosceles triangle having base 'Y' cm and one side 'Y' cm?

A.  \[\frac{x}{2}\sqrt{{{y}^{2}}+\frac{{{x}^{2}}}{4}}c{{m}^{2}}\]
B.  \[\frac{x}{2}\sqrt{\frac{4{{y}^{2}}-{{x}^{2}}}{4}}c{{m}^{2}}\]
C.  \[\frac{{{x}^{2}}-{{y}^{2}}}{4}c{{m}^{2}}\]
D.  \[\frac{{{x}^{2}}+{{y}^{2}}}{4}c{{m}^{2}}\]
Answer» C.  \[\frac{{{x}^{2}}-{{y}^{2}}}{4}c{{m}^{2}}\]


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