1.

What is \(\mathop \smallint \nolimits_0^{\rm{\pi }} {{\rm{e}}^{\rm{x}}}\sin {\rm{x}}\) dx equal to?

A. \(\frac{{{{\rm{e}}^{\rm{\pi }}} + 1}}{2}\)
B. \(\frac{{{{\rm{e}}^{\rm{\pi }}} - 1}}{2}\)
C. eπ + 1
D. \(\frac{{{{\rm{e}}^{\rm{\pi }}} + 1}}{4}\)
Answer» B. \(\frac{{{{\rm{e}}^{\rm{\pi }}} - 1}}{2}\)


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