\(\rm \frac {\left( p^2 - q^2 \right) \cos \theta}{p \cos \theta + q \sin \theta}\)

\(\rm \frac {\left( p^2 + q^2 \right) \sin \theta}{p \cos \theta + q \sin \theta}\)

\(\rm \frac {\left( p^2 + q^2 \right) \sin \theta}{q \cos \theta + p \sin \theta}\)

\(\rm \frac {\left( p^2 - q^2 \right) \cos \theta}{q \cos \theta + p \sin \theta}\)

What is AB equal to?

1.	What is AB equal to?
A.	\(\rm \frac {\left( p^2 + q^2 \right) \sin \theta}{p \cos \theta + q \sin \theta}\)
B.	\(\rm \frac {\left( p^2 - q^2 \right) \cos \theta}{p \cos \theta + q \sin \theta}\)
C.	\(\rm \frac {\left( p^2 + q^2 \right) \sin \theta}{q \cos \theta + p \sin \theta}\)
D.	\(\rm \frac {\left( p^2 - q^2 \right) \cos \theta}{q \cos \theta + p \sin \theta}\)
Answer» B. \(\rm \frac {\left( p^2 - q^2 \right) \cos \theta}{p \cos \theta + q \sin \theta}\)

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