Total energy of an absorbed photon in eV is(a) $\frac{{12400}}{{\lambda \left( {\dot A} \right)}}$(b) $\frac{{11400}}{{\lambda \left( {\dot A} \right)}}$(c) $\frac{{1200}}{{\lambda \left( {\dot A} \right)}}$(d) $\frac{{\lambda\left( {\dot A} \right)}}{{11400 }}$Codes:

Question

TuteeHUB · Accepted Answer

(c) is correct but (d) is wrong

TuteeHUB · Answer

(a) and (b) are correct

TuteeHUB · Answer

(a) is correct but (c) is wrong

TuteeHUB · Answer

(d) is correct but (a) is wrong

1.	Total energy of an absorbed photon in eV is(a) \(\frac{{12400}}{{\lambda \left( {\dot A} \right)}}\)(b) \(\frac{{11400}}{{\lambda \left( {\dot A} \right)}}\)(c) \(\frac{{1200}}{{\lambda \left( {\dot A} \right)}}\)(d) \(\frac{{\lambda\left( {\dot A} \right)}}{{11400 }}\)Codes:
A.	(a) and (b) are correct
B.	(a) is correct but (c) is wrong
C.	(c) is correct but (d) is wrong
D.	(d) is correct but (a) is wrong
Answer» C. (c) is correct but (d) is wrong

Total energy of an absorbed photon in eV is(a) \(\frac{{12400}}{{\lambda \left( {\dot A} \right)}}\)(b) \(\frac{{11400}}{{\lambda \left( {\dot A} \right)}}\)(c) \(\frac{{1200}}{{\lambda \left( {\dot A} \right)}}\)(d) \(\frac{{\lambda\left( {\dot A} \right)}}{{11400 }}\)Codes:

Discussion

No Comment Found

Related MCQs

Reply to Comment