To reduce the differential equation \({\left( {x + 5} \right)^2}\frac{{{d^2}y}}{{d{x^2}}} - \left( {x + 5} \right)\frac{{dy}}{{dx}} + y = 10x + 8\) to linear differential equation with constant coefficient, the substitution is

• A. x + 5 = e-z
• B. x + 5 = ez
• C. z = ex + 5
• D. z = x + 5