MCQOPTIONS
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| 1. |
Time taken to enter a byte in parallel shift register using clock of 5 MHz is __________.(Neglect propagation time delay of flip flops) |
| A. | 0.2 micro seconds |
| B. | 5 micro seconds |
| C. | 40 micro seconds |
| D. | 18 micro seconds |
| Answer» B. 5 micro seconds | |