1.

Three identical impedances, each of (9.8 + j10) Ω, are connected to a 400 V, 50 Hz, AC power supply. The power supplied to the load is measured by the two-wattmeter method. If the impedances are connected in a delta, find the readings of the two wattmeters.

A. W1 = -4.4 kW and W2 = 1 kW
B. W1 = 1 kW and W2 = 4.4 kW
C. W1 = 19 kW and W2 = 4.9 kW
D. W1 = 6.36 kW and W2 = 1.64 kW
Answer» D. W1 = 6.36 kW and W2 = 1.64 kW


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