The z-transform corresponding to the Laplace transform G(s) = 10 / s(s + 5) is

Question

TuteeHUB · Accepted Answer

$\frac{{{e^{ - 5T}}}}{{{{\left( {z - 1} \right)}^2}}}$

TuteeHUB · Answer

$\frac{{2z{e^{ - 5T}}}}{{\left( {z - 1} \right)\left( {z - {e^{ - T}}} \right)}}$

TuteeHUB · Answer

$\frac{{2z\left( {1 - {e^{ - 5t}}} \right)}}{{\left( {z - 1} \right)\left( {z - {e^{ - 5t}}} \right)}}$

TuteeHUB · Answer

$\frac{{{e^{ - T}}}}{{\left( {z - 1} \right)\left( {z - {e^{ - 5t}}} \right)}}$

1.	The z-transform corresponding to the Laplace transform G(s) = 10 / s(s + 5) is
A.	\(\frac{{2z{e^{ - 5T}}}}{{\left( {z - 1} \right)\left( {z - {e^{ - T}}} \right)}}\)
B.	\(\frac{{2z\left( {1 - {e^{ - 5t}}} \right)}}{{\left( {z - 1} \right)\left( {z - {e^{ - 5t}}} \right)}}\)
C.	\(\frac{{{e^{ - 5T}}}}{{{{\left( {z - 1} \right)}^2}}}\)
D.	\(\frac{{{e^{ - T}}}}{{\left( {z - 1} \right)\left( {z - {e^{ - 5t}}} \right)}}\)
Answer» C. \(\frac{{{e^{ - 5T}}}}{{{{\left( {z - 1} \right)}^2}}}\)

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