The velocity profile in fully developed laminar flow in a pipe of diameter D is given by $u = {u_0}\left( {1 - \frac{{4{r^2}}}{{{D^2}}}} \right)$, where r is the radial distance from the center. If the viscosity of the fluid is μ, the pressure drop across a length L of the pipe is:

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TuteeHUB · Answer

$\frac{{\mu {u_0}L}}{{{D^2}}}$

TuteeHUB · Answer

$\frac{{4\mu {u_0}L}}{{{D^2}}}$

TuteeHUB · Answer

$\frac{{8\mu {u_0}L}}{{{D^2}}}$

TuteeHUB · Answer

$\frac{{16\mu {u_0}L}}{{{D^2}}}$

1.	The velocity profile in fully developed laminar flow in a pipe of diameter D is given by \(u = {u_0}\left( {1 - \frac{{4{r^2}}}{{{D^2}}}} \right)\), where r is the radial distance from the center. If the viscosity of the fluid is μ, the pressure drop across a length L of the pipe is:
A.	\(\frac{{\mu {u_0}L}}{{{D^2}}}\)
B.	\(\frac{{4\mu {u_0}L}}{{{D^2}}}\)
C.	\(\frac{{8\mu {u_0}L}}{{{D^2}}}\)
D.	\(\frac{{16\mu {u_0}L}}{{{D^2}}}\)
Answer» E.

The velocity profile in fully developed laminar flow in a pipe of diameter D is given by \(u = {u_0}\left( {1 - \frac{{4{r^2}}}{{{D^2}}}} \right)\), where r is the radial distance from the center. If the viscosity of the fluid is μ, the pressure drop across a length L of the pipe is:

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