The value of (x−y)3+(y−z)3+(z−x)3(x2−y2)3+(y2−z2)3+(z2−x2)3 is = ?(x−y)3+(y−z)3+(z−x)3(x2−y2)3+(y2−z2)3+(z2−x2)3 is = ?

• A. 0
• B. 1
• C. [2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)]−1[2(x+y+z)][2(x+y+z)][2(x+y+z)2(x+y+z)2(x+y+z)(x+y+zx+y+zx+y+z)]−1−1−1−1[2(x+y+z)]−1
• D. [(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)]−1[(x+y)(y+z)(z+x)][(x+y)(y+z)(z+x)][(x+y)(y+z)(z+x)(x+y)(y+z)(z+x)(x+y)(x+yx+yx+y)(y+z)(y+zy+zy+z)(z+x)(z+xz+xz+x)]−1−1−1−1[(x+y)(y+z)(z+x)]−1