The value of \(\sum\limits_{r = 1}^9 {{{\sin }^2}\left( {\frac{{r\pi }}{{18}}} \right)} \) is

The value of \(\sum\limits_{r = 1}^9 {{{\sin }^2}\left( {\frac{{r\pi

1.	The value of \(\sum\limits_{r = 1}^9 {{{\sin }^2}\left( {\frac{{r\pi }}{{18}}} \right)} \) is
A.	1
B.	0
C.	5
D.	π
Answer» D. π