The value of $\smallint \frac{1}{{\left( {x + 1} \right)\sqrt {{x^2} - 1} }}dx$ will be ______, where C is an arbitrary constant.

Question

The value of $\smallint \frac{1}{{\left( {x + 1} \right)\sqrt {{x^2} - 1} }}dx$ will be ______, where C is an arbitrary constant.

TuteeHUB · Accepted Answer

$log {\frac{{{x} + 1}}{{{x} - 1}} + C} $

TuteeHUB · Answer

$\sqrt {\frac{{{x^2} + 1}}{{{x^2} - 1}} + C} $

TuteeHUB · Answer

$\sqrt {\frac{{{x} - 1}}{{{x} + 1}}} + C$

TuteeHUB · Answer

$log {\frac{{{x^2} - 1}}{{{x^2}+ 1}} + C} $

1.	The value of \(\smallint \frac{1}{{\left( {x + 1} \right)\sqrt {{x^2} - 1} }}dx\) will be ______, where C is an arbitrary constant.
A.	\(\sqrt {\frac{{{x^2} + 1}}{{{x^2} - 1}} + C} \)
B.	\(\sqrt {\frac{{{x} - 1}}{{{x} + 1}}} + C\)
C.	\(log {\frac{{{x} + 1}}{{{x} - 1}} + C} \)
D.	\(log {\frac{{{x^2} - 1}}{{{x^2}+ 1}} + C} \)
Answer» C. \(log {\frac{{{x} + 1}}{{{x} - 1}} + C} \)

The value of \(\smallint \frac{1}{{\left( {x + 1} \right)\sqrt {{x^2} - 1} }}dx\) will be ______, where C is an arbitrary constant.