The value of $si{n^{ - 1}}\left( {\frac{{12}}{{13}}} \right) - si{n^{ - 1}}\left( {\frac{3}{5}} \right)$ is equal to:

Question

The value of $si{n^{ - 1}}\left( {\frac{{12}}{{13}}} \right) - si{n^{ - 1}}\left( {\frac{3}{5}} \right)$ is equal to:

TuteeHUB · Accepted Answer

$\frac{\pi }{2} - si{n^{ - 1}}\left( {\frac{{56}}{{65}}} \right)$

TuteeHUB · Answer

$\pi - co{s^{ - 1}}\left( {\frac{{63}}{{65}}} \right)$

TuteeHUB · Answer

$\frac{\pi }{2} - co{s^{ - 1}}\left( {\frac{9}{{65}}} \right)$

TuteeHUB · Answer

$\pi - co{s^{ - 1}}\left( {\frac{{33}}{{65}}} \right)$

1.	The value of \(si{n^{ - 1}}\left( {\frac{{12}}{{13}}} \right) - si{n^{ - 1}}\left( {\frac{3}{5}} \right)\) is equal to:
A.	\(\pi - co{s^{ - 1}}\left( {\frac{{63}}{{65}}} \right)\)
B.	\(\frac{\pi }{2} - si{n^{ - 1}}\left( {\frac{{56}}{{65}}} \right)\)
C.	\(\frac{\pi }{2} - co{s^{ - 1}}\left( {\frac{9}{{65}}} \right)\)
D.	\(\pi - co{s^{ - 1}}\left( {\frac{{33}}{{65}}} \right)\)
Answer» B. \(\frac{\pi }{2} - si{n^{ - 1}}\left( {\frac{{56}}{{65}}} \right)\)

The value of \(si{n^{ - 1}}\left( {\frac{{12}}{{13}}} \right) - si{n^{ - 1}}\left( {\frac{3}{5}} \right)\) is equal to: