The value of \(\frac{1}{\sec \text{x}-\tan \text{x}}-\frac{1}{\cos \text{x}}\) 0°Free Practice With Testbook Mock TestsSSC CGL Mock Test 2020374 Total Tests | 8 Free TestsCurrent Affairs for SSC/Railways 2021 Mock Test97 Total Tests | 5 Free TestsOptions: tan x cot x 2cos x 2sec x Correct Answer: Option 1 (Solution Below)This question was previously asked inSSC CGL Previous Paper 49 (Held On: 7 June 2019 Shift 1)Download PDF ››Attempt Online ››Solution: Download Question With Solution PDF ››\(\frac{1}{{\sec x{\rm{\;}}-\tan x{\rm{\;\;}}}} - \frac{1}{{\cos x}}\)\(\Rightarrow \frac{1}{{\frac{1}{{\cos x}} - \frac{{\sin x}}{{\cos x}}}} - \frac{1}{{\cos x}}\)\(\Rightarrow \frac{{\cos x}}{{\left( {1{\rm{\;}} - {\rm{\;}}\sin x} \right)}} - \frac{1}{{\cos x}}\)\(\Rightarrow \frac{{{\rm{co}}{{\rm{s}}^2}{\rm{x}} - 1 + \sin x{\rm{\;\;}}}}{{\cos x{\rm{\;}}\left( {1 - \sin x} \right){\rm{\;}}}}\)\(\Rightarrow \frac{{1 - {\rm{si}}{{\rm{n}}^2}{\rm{x}} - 1 + \sin x}}{{\cos x\left( {{\rm{\;}}1 - \sin x} \right)}}\)\(\Rightarrow \frac{{\sin x\left( {{\rm{\;}}1 - \sin x} \right)}}{{\cos x\left( {1 - \sin x} \right)}}\)⇒ tanxDownload Question With Solution PDF ››

• A. tan x
• B. cot x
• C. 2cos x
• D. 2sec x