1.

The value of 27a3 – 2√2b3 is equal to:

A. (3a – √2b)(9a2 + 2b2 + 3√2 ab)
B. (3a – √2b)(9a2 + 2b2 + 6√2 ab)
C. (3a – √2b)(9a2 – 2b2 + 6√2 ab)
D. (3a – √2b)(9a2 – 2b2 – 3√2 ab)
Answer» B. (3a – √2b)(9a2 + 2b2 + 6√2 ab)


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