The unilateral Laplace transform of f(t) is\(\frac{1}{{{s^2} + s + 1}}\) . Which one of the following is the unilateral Laplace transform of g(t) = t ⋅ f(t)?

\(\frac{{ - s}}{{\left( {{s^2} + s + 1} \right)}}\)

\(\frac{{ - \left( {2s + 1} \right)}}{{{{\left( {{s^2} + s + 1} \right)}^2}}}\)

\(\frac{s}{{{{\left( {{s^2} + s + 1} \right)}^2}}}\)

\(\frac{{2s + 1}}{{{{\left( {{s^2} + s + 1} \right)}^2}}}\)

The unilateral Laplace transform of f(t) is\(\frac{1}{{{s^2} + s + 1}}

1.	The unilateral Laplace transform of f(t) is\(\frac{1}{{{s^2} + s + 1}}\) . Which one of the following is the unilateral Laplace transform of g(t) = t ⋅ f(t)?
A.	\(\frac{{ - s}}{{\left( {{s^2} + s + 1} \right)}}\)
B.	\(\frac{{ - \left( {2s + 1} \right)}}{{{{\left( {{s^2} + s + 1} \right)}^2}}}\)
C.	\(\frac{s}{{{{\left( {{s^2} + s + 1} \right)}^2}}}\)
D.	\(\frac{{2s + 1}}{{{{\left( {{s^2} + s + 1} \right)}^2}}}\)
Answer» E.