The unilateral Laplace transform of f(t) is $\frac{1}{{{s^2} + 2s + 1}}$. The unilateral Laplace transform of tf(t) is

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$ - \frac{s}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}$

TuteeHUB · Answer

$ - \frac{{2s + 2}}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}$

TuteeHUB · Answer

$\frac{s}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}$

TuteeHUB · Answer

$\frac{{2s + 2}}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}$

1.	The unilateral Laplace transform of f(t) is \(\frac{1}{{{s^2} + 2s + 1}}\). The unilateral Laplace transform of tf(t) is
A.	\( - \frac{s}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}\)
B.	\( - \frac{{2s + 2}}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}\)
C.	\(\frac{s}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}\)
D.	\(\frac{{2s + 2}}{{{{\left( {{s^2} + 2s + 1} \right)}^2}}}\)
Answer» E.

The unilateral Laplace transform of f(t) is \(\frac{1}{{{s^2} + 2s + 1}}\). The unilateral Laplace transform of tf(t) is