MCQOPTIONS
Saved Bookmarks
| 1. |
The torque expression of a current carrying conductor is |
| A. | T = BIA cos θ |
| B. | T = BA cos θ |
| C. | T = BIA sin θ |
| D. | T = BA sin θ |
| Answer» D. T = BA sin ‚âà√≠‚Äö√†√® | |