The stiffness matrix of a beam is given as $K = \left[ {\begin{array}{*{20}{c}} {12}&4\ 4&5 \end{array}} \right]$ Calculate the flexibility matrix. Flexibility matrix will be ______.

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The stiffness matrix of a beam is given as $K = \left[ {\begin{array}{*{20}{c}} {12}&4\ 4&5 \end{array}} \right]$ Calculate the flexibility matrix. Flexibility matrix will be ______.

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\frac{K}{{44}}\left[ {\begin{array}{*{20}{c}} {12}&{ - 4}\ { - 4}&5 \end{array}} \right]$

TuteeHUB · Answer

$\frac{K}{{44}}\left[ {\begin{array}{*{20}{c}} {12}&4\ 4&5 \end{array}} \right]$

TuteeHUB · Answer

$\frac{1}{{44}}\left[ {\begin{array}{*{20}{c}} {12}&{ - 4}\ { - 4}&5 \end{array}} \right]$

TuteeHUB · Answer

$\frac{1}{{44}}\left[ {\begin{array}{*{20}{c}} 5&{ - 4}\ { - 4}&{12} \end{array}} \right]$

1.	The stiffness matrix of a beam is given as \(K = \left[ {\begin{array}{*{20}{c}} {12}&4\\ 4&5 \end{array}} \right]\) Calculate the flexibility matrix. Flexibility matrix will be ______.
A.	\(\frac{K}{{44}}\left[ {\begin{array}{*{20}{c}} {12}&{ - 4}\\ { - 4}&5 \end{array}} \right]\)
B.	\(\frac{K}{{44}}\left[ {\begin{array}{*{20}{c}} {12}&4\\ 4&5 \end{array}} \right]\)
C.	\(\frac{1}{{44}}\left[ {\begin{array}{*{20}{c}} {12}&{ - 4}\\ { - 4}&5 \end{array}} \right]\)
D.	\(\frac{1}{{44}}\left[ {\begin{array}{*{20}{c}} 5&{ - 4}\\ { - 4}&{12} \end{array}} \right]\)
Answer» E.

The stiffness matrix of a beam is given as \(K = \left[ {\begin{array}{*{20}{c}} {12}&4\\ 4&5 \end{array}} \right]\) Calculate the flexibility matrix. Flexibility matrix will be ______.

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