The solution of the differential equation $y = px + \sqrt {4 + {p^2}} $ is

Question

The solution of the differential equation $y = px + \sqrt {4 + {p^2}} $ is

TuteeHUB · Accepted Answer

${\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} - {\rm{ }}{4C^2} = {\rm{ }}0$

TuteeHUB · Answer

${\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} + {\rm{ }}{C^2} = {\rm{ }}0$

TuteeHUB · Answer

${\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} + {\rm{ }}{4C^2} = {\rm{ }}0$

TuteeHUB · Answer

${\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} - {\rm{ }}{C^2} = {\rm{ }}4$

1.	The solution of the differential equation \(y = px + \sqrt {4 + {p^2}} \) is
A.	\({\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} + {\rm{ }}{C^2} = {\rm{ }}0\)
B.	\({\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} + {\rm{ }}{4C^2} = {\rm{ }}0\)
C.	\({\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} - {\rm{ }}{C^2} = {\rm{ }}4\)
D.	\({\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} - {\rm{ }}{4C^2} = {\rm{ }}0\)
Answer» D. \({\left( {y{\rm{ }} - {\rm{ }}Cx} \right)^2} - {\rm{ }}{4C^2} = {\rm{ }}0\)

The solution of the differential equation \(y = px + \sqrt {4 + {p^2}} \) is