The solution of the differential equation, \(\frac{{{\rm{d}}y}}{{{\rm{d}}x}} = {(x - y)^2}\) when y(1) = 1, is:

• A. \({\rm{lo}}{{\rm{g}}_{\rm{e}}}\left| {\frac{{2 - x}}{{2 - y}}} \right| = x - y\)
• B. \(- {\rm{lo}}{{\rm{g}}_{\rm{e}}}\left| {\frac{{1 - x + y}}{{1 + x - y}}} \right| = 2\left( {x - 1} \right)\)
• C. \(- {\rm{lo}}{{\rm{g}}_{\rm{e}}}\left| {\frac{{1 + x - y}}{{1 - x + y}}} \right| = x + y - 2\)
• D. \({\rm{lo}}{{\rm{g}}_{\rm{e}}}\left| {\frac{{2 - y}}{{2 - x}}} \right| = 2\left( {y - 1} \right)\)