MCQOPTIONS
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| 1. |
The solution of the differential equation \(\frac{{dy}}{{dx}} + 2xy = {e^{ - {x^2}}}\) with y (0) = 1 is : |
| A. | \(\left( {1 + x} \right){e^{ + {x^2}}}\) |
| B. | \(\left( {1 + x} \right){e^{ - {x^2}}}\) |
| C. | \(\left( {1 - x} \right){e^{ + {x^2}}}\) |
| D. | \(\left( {1 - x} \right){e^{ - {x^2}}}\) |
| Answer» C. \(\left( {1 - x} \right){e^{ + {x^2}}}\) | |