1.

The solution of the differential equation \(\frac{{dy}}{{dx}} + 2xy = {e^{ - {x^2}}}\) with y (0) = 1 is :

A. \(\left( {1 + x} \right){e^{ + {x^2}}}\)
B. \(\left( {1 + x} \right){e^{ - {x^2}}}\)
C. \(\left( {1 - x} \right){e^{ + {x^2}}}\)
D. \(\left( {1 - x} \right){e^{ - {x^2}}}\)
Answer» C. \(\left( {1 - x} \right){e^{ + {x^2}}}\)


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