MCQOPTIONS
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| 1. |
The solution of the differential equation\(\frac{{{d^2}y}}{{d{x^2}}} - 3\frac{{dy}}{{dx}} + 2y = {e^{3x}}\) |
| A. | \(y = a{e^x} + b{e^{2x}} + \frac{1}{2}{e^{3x}}\) |
| B. | \(y = a{e^{ - x}} + b{e^{ - 2x}} + \frac{1}{2}{e^{ - 3x}}\) |
| C. | \(y = a{e^x} + b{e^{ - 2x}} + \frac{1}{2}{e^{3x}}\) |
| D. | \(y = a{e^{ - x}} + b{e^{2x}} + \frac{1}{2}{e^{3x}}\) |
| Answer» B. \(y = a{e^{ - x}} + b{e^{ - 2x}} + \frac{1}{2}{e^{ - 3x}}\) | |