1.

The solution of the differential equation\(\frac{{{d^2}y}}{{d{x^2}}} - 3\frac{{dy}}{{dx}} + 2y = {e^{3x}}\)

A. \(y = a{e^x} + b{e^{2x}} + \frac{1}{2}{e^{3x}}\)
B. \(y = a{e^{ - x}} + b{e^{ - 2x}} + \frac{1}{2}{e^{ - 3x}}\)
C. \(y = a{e^x} + b{e^{ - 2x}} + \frac{1}{2}{e^{3x}}\)
D. \(y = a{e^{ - x}} + b{e^{2x}} + \frac{1}{2}{e^{3x}}\)
Answer» B. \(y = a{e^{ - x}} + b{e^{ - 2x}} + \frac{1}{2}{e^{ - 3x}}\)


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