1.

The solution of the differential equation(1 + y2)dx = (tan-1 y - x)dy is

A. \(x = {\tan ^{ - 1}}y + 1 + c{e^{ - {{\tan }^{ - 1}}y}}\)
B. \(x = {\tan ^{ - 1}}y - 1 + c{e^{ - {{\tan }^{ - 1}}y}}\)
C. \(x = \frac{1}{2}{\tan ^{ - 1}}y - 1 + c{e^{ - {{\tan }^{ - 1}}y}}\)
D. \(x = \frac{1}{2}{\tan ^{ - 1}}y + 1 + c{e^{ - {{\tan }^{ - 1}}y}}\)
Answer» C. \(x = \frac{1}{2}{\tan ^{ - 1}}y - 1 + c{e^{ - {{\tan }^{ - 1}}y}}\)


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