MCQOPTIONS
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| 1. |
The solution of \(\frac{{dy}}{{dx}} = {y^2}\) with initial value y(0) = 1 is bounded in the interval |
| A. | \(- \infty \; \le \;x\; \le \;\infty\) |
| B. | \(- \infty \; \le \;x\; \le \;1\) |
| C. | \(x<1,\ x>1\) |
| D. | \(- 2\; \le \;x\; \le \;2\) |
| Answer» D. \(- 2\; \le \;x\; \le \;2\) | |