1.

The solution of \(\frac{{dy}}{{dx}} = {y^2}\) with initial value y(0) = 1 is bounded in the interval

A. \(- \infty \; \le \;x\; \le \;\infty\)
B. \(- \infty \; \le \;x\; \le \;1\)
C. \(x<1,\ x>1\)
D. \(- 2\; \le \;x\; \le \;2\)
Answer» D. \(- 2\; \le \;x\; \le \;2\)


Discussion

No Comment Found