1.

The solution of differential equation un+3 - 4un+2 + un+1 + 6un = 0 will be:

A. un = C1(1)n +C2(2)n + C3(3)n, where C1, C2, C3 are constants.
B. un = C1(-1)n +C2(-2)n + C3(-3)n, where C1, C2, C3 are constants.
C. un = C1(1)n + C2(-2)n + C2(3)n, where C1, C2, C2 are constants.
D. un = C1 (-1)n + C2(2)n + C3(3)n, where C1, C2, C3 are constants.
Answer» E.


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