MCQOPTIONS
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MCQOPTIONS
| 1. |
The solution for the differential equation\(\frac{{{d^2}x}}{{d{t^2}}} = - 9x\)With initial conditions \(x\left( 0 \right) = 1\ and\ \frac{{dx}}{{dt}}{|_{t = 0}} = 1\), is |
| A. | t2 + t + 1 |
| B. | \(sin\ 3t + \frac{1}{3}\cos 3t + \frac{2}{3}\) |
| C. | \(\frac{1}{{3}}\sin 3t + \cos 3t\) |
| D. | cos 3t + t |
| Answer» D. cos 3t + t | |