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The simplest rationalizing factor of \[\frac{{{6}^{n+3}}-{{32.6}^{n+1}}}{{{6}^{n+2}}-{{2.6}^{n+1}}}=\frac{{{6}^{n+1}}.(36-32)}{{{6}^{n+1}}(6-2)}=1.\] is

A.  \[p,q,r,s,l,m\in I,q\ne 0,s\ne 0,m\ne 0.\]                                  
B.  \[a+b=b+a\]
C.  \[a\times b=b\times a\]                                  
D. none of these
Answer» C.  \[a\times b=b\times a\]                                  


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