MCQOPTIONS
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MCQOPTIONS
| 1. |
The relation between work (W) against electric field and electric flux density \(\vec D\) is given by: |
| A. | \(W = \frac{1}{2}\smallint \frac{{{D^2}}}{\varepsilon }dv\) |
| B. | \(W = \frac{1}{2}\smallint \varepsilon {D^2}\) |
| C. | \(W = \smallint {D^2}dv\) |
| D. | \(W = \frac{1}{2}\smallint {D^2}dv\) |
| Answer» B. \(W = \frac{1}{2}\smallint \varepsilon {D^2}\) | |