The product of \[\left( x-\frac{1}{x} \right)\left( x+\frac{1}{x} \right)\left( {{x}^{2}}+\frac{1}{{{x}^{2}}} \right)\left( {{x}^{4}}+\frac{1}{{{x}^{4}}} \right)\] is

\[\left( {{x}^{4}}-\frac{1}{{{x}^{4}}} \right)\]

\[\left( {{x}^{8}}-\frac{1}{{{x}^{8}}} \right)\]

\[\left( {{x}^{2}}-\frac{1}{{{x}^{2}}} \right)\]

\[\left( {{x}^{8}}+\frac{1}{{{x}^{8}}} \right)\]

The product of \[\left( x-\frac{1}{x} \right)\left( x+\frac{1}{x} \rig

1.	The product of \[\left( x-\frac{1}{x} \right)\left( x+\frac{1}{x} \right)\left( {{x}^{2}}+\frac{1}{{{x}^{2}}} \right)\left( {{x}^{4}}+\frac{1}{{{x}^{4}}} \right)\] is
A.	\[\left( {{x}^{8}}-\frac{1}{{{x}^{8}}} \right)\]
B.	\[\left( {{x}^{4}}-\frac{1}{{{x}^{4}}} \right)\]
C.	\[\left( {{x}^{2}}-\frac{1}{{{x}^{2}}} \right)\]
D.	\[\left( {{x}^{8}}+\frac{1}{{{x}^{8}}} \right)\]
Answer» B. \[\left( {{x}^{4}}-\frac{1}{{{x}^{4}}} \right)\]