The product of \[\left( \mathbf{x-}\frac{\mathbf{1}}{\mathbf{x}} \right)\left( \mathbf{x+}\frac{\mathbf{1}}{\mathbf{x}} \right)\left( {{\mathbf{x}}^{\mathbf{2}}}\mathbf{+}\frac{\mathbf{1}}{{{\mathbf{x}}^{\mathbf{2}}}} \right)\left( {{\mathbf{x}}^{\mathbf{4}}}\mathbf{+}\frac{\mathbf{1}}{{{\mathbf{x}}^{\mathbf{4}}}} \right)\]is

\[\left( {{x}^{4}}-\frac{1}{{{x}^{4}}} \right)\]

\[\left( {{x}^{8}}-\frac{1}{{{x}^{8}}} \right)\]

\[\left( {{x}^{2}}-\frac{1}{{{x}^{2}}} \right)\]

\[\left( {{x}^{8}}+\frac{1}{{{x}^{8}}} \right)\]

The product of \[\left( \mathbf{x-}\frac{\mathbf{1}}{\mathbf{x}} \righ

1.	The product of \[\left( \mathbf{x-}\frac{\mathbf{1}}{\mathbf{x}} \right)\left( \mathbf{x+}\frac{\mathbf{1}}{\mathbf{x}} \right)\left( {{\mathbf{x}}^{\mathbf{2}}}\mathbf{+}\frac{\mathbf{1}}{{{\mathbf{x}}^{\mathbf{2}}}} \right)\left( {{\mathbf{x}}^{\mathbf{4}}}\mathbf{+}\frac{\mathbf{1}}{{{\mathbf{x}}^{\mathbf{4}}}} \right)\]is
A.	\[\left( {{x}^{8}}-\frac{1}{{{x}^{8}}} \right)\]
B.	\[\left( {{x}^{4}}-\frac{1}{{{x}^{4}}} \right)\]
C.	\[\left( {{x}^{2}}-\frac{1}{{{x}^{2}}} \right)\]
D.	\[\left( {{x}^{8}}+\frac{1}{{{x}^{8}}} \right)\]
Answer» B. \[\left( {{x}^{4}}-\frac{1}{{{x}^{4}}} \right)\]

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