The Poynting vector on the surface of a long straight conductor of radius a and conductivity σ0, which carries current I in the z-direction, is

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\frac{{{I^2}}}{{{\sigma _0}\pi {b^3}}}{\hat a_r}$

TuteeHUB · Answer

$\frac{{ - {I^2}}}{{2{\sigma _0}{\pi ^2}{a^2}}}{\hat a_r}$

TuteeHUB · Answer

$\frac{{{I^2}}}{{{\sigma _0}{\pi ^2}{a^3}}}{\hat a_r}$

TuteeHUB · Answer

$\frac{{ - {I^2}}}{{2{\sigma _0}{\pi ^2}{a^3}}}{\hat a_r}$

1.	The Poynting vector on the surface of a long straight conductor of radius a and conductivity σ0, which carries current I in the z-direction, is
A.	\(\frac{{{I^2}}}{{{\sigma _0}\pi {b^3}}}{\hat a_r}\)
B.	\(\frac{{ - {I^2}}}{{2{\sigma _0}{\pi ^2}{a^2}}}{\hat a_r}\)
C.	\(\frac{{{I^2}}}{{{\sigma _0}{\pi ^2}{a^3}}}{\hat a_r}\)
D.	\(\frac{{ - {I^2}}}{{2{\sigma _0}{\pi ^2}{a^3}}}{\hat a_r}\)
Answer» E.

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