MCQOPTIONS
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MCQOPTIONS
| 1. |
The position of a particle as a function of time t, is given byx(t) = at + bt2 – ct3where, a, b and c are constants. When the particle attains zero acceleration, then its velocity will be: |
| A. | \(a + \frac{{{b^2}}}{{4c}}\) |
| B. | \(a + \frac{{{b^2}}}{{3c}}\) |
| C. | \(a + \frac{{{b^2}}}{c}\) |
| D. | \(a + \frac{{{b^2}}}{{2c}}\) |
| Answer» C. \(a + \frac{{{b^2}}}{c}\) | |