MCQOPTIONS
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| 1. |
The period of oscillation of a simple pendulum is given by \[T=2\pi \sqrt{\frac{l}{g}}\]where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1 s. The percentage error in g is |
| A. | 0.1% |
| B. | 1% |
| C. | 0.2% |
| D. | 0.8% |
| Answer» D. 0.8% | |