The partial fraction expansion of the function $F\left( z \right) = \frac{{4{z^2} - 2z}}{{{z^3} - 5{z^2} + 8z - 4}}$ is

Question

The partial fraction expansion of the function $F\left( z \right) = \frac{{4{z^2} - 2z}}{{{z^3} - 5{z^2} + 8z - 4}}$ is

TuteeHUB · Accepted Answer

$\frac{{1.5}}{{z - 1}} + \frac{{12}}{{\left( {z - 1} \right)\left( {z - 2} \right)}}$

TuteeHUB · Answer

$\frac{2}{{z - 1}} + \frac{{12}}{{{{\left( {z - 2} \right)}^2}}}$

TuteeHUB · Answer

$\frac{2}{{z - 1}} + \frac{2}{{z - 2}} + \frac{{12}}{{{{\left( {z - 2} \right)}^2}}}$

TuteeHUB · Answer

$\frac{{1.5}}{{z - 1}} + \frac{{1.5}}{{z - 2}} + \frac{1}{{{{\left( {z - 2} \right)}^2}}}$

1.	The partial fraction expansion of the function \(F\left( z \right) = \frac{{4{z^2} - 2z}}{{{z^3} - 5{z^2} + 8z - 4}}\) is
A.	\(\frac{2}{{z - 1}} + \frac{{12}}{{{{\left( {z - 2} \right)}^2}}}\)
B.	\(\frac{2}{{z - 1}} + \frac{2}{{z - 2}} + \frac{{12}}{{{{\left( {z - 2} \right)}^2}}}\)
C.	\(\frac{{1.5}}{{z - 1}} + \frac{{12}}{{\left( {z - 1} \right)\left( {z - 2} \right)}}\)
D.	\(\frac{{1.5}}{{z - 1}} + \frac{{1.5}}{{z - 2}} + \frac{1}{{{{\left( {z - 2} \right)}^2}}}\)
Answer» C. \(\frac{{1.5}}{{z - 1}} + \frac{{12}}{{\left( {z - 1} \right)\left( {z - 2} \right)}}\)

The partial fraction expansion of the function \(F\left( z \right) = \frac{{4{z^2} - 2z}}{{{z^3} - 5{z^2} + 8z - 4}}\) is