1.

The output of the code shown below is: odd=lambda x: bool(x%2) numbers=[n for n in range(10)] print(numbers) n=list() for i in numbers: if odd(i): continue else: break

A. [0, 2, 4, 6, 8, 10]
B. [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
C. [1, 3, 5, 7, 9]
D. Error
Answer» C. [1, 3, 5, 7, 9]


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