MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
| 1. |
The number of ways in which a Schottky defect can occur in silicon is given by:(N = total no. of atoms in a crystal of unit volumens = number of Schottky defects per unit volume) |
| A. | \(\dfrac{N!}{\left(N-n_s\right)!}\) |
| B. | \(\dfrac{N!}{n_s!}\) |
| C. | \(\dfrac{N!}{N-n_s!}\) |
| D. | \(\dfrac{N!}{\left(N-n_s\right)!n_s!}\) |
| Answer» E. | |