The N-point DFT of a sequence x[n] ; 0 ≤ n ≤ N -1 is given by \(\rm X\left[ k \right] = \frac{1}{{\sqrt N }}\mathop \sum \limits_{n = 0}^{N - 1} x\left( n \right){e^{\frac{{ - j2\pi nk}}{N}}};\;0 \le k \le N - 1\). Denote this relation as \(\rm X\left[k\right] = \;DFT\left\{ {x\left[ n \right]} \right\}\).For N = 4 which one of the following sequences satisfies \(\rm DFT\;\left( {DFT\left\{ {x\left[ n \right]} \right\}} \right) = x\left[ n \right]\)

The N-point DFT of a sequence x[n] ; 0 ≤ n ≤ N -1 is given by

1.	The N-point DFT of a sequence x[n] ; 0 ≤ n ≤ N -1 is given by \(\rm X\left[ k \right] = \frac{1}{{\sqrt N }}\mathop \sum \limits_{n = 0}^{N - 1} x\left( n \right){e^{\frac{{ - j2\pi nk}}{N}}};\;0 \le k \le N - 1\). Denote this relation as \(\rm X\left[k\right] = \;DFT\left\{ {x\left[ n \right]} \right\}\).For N = 4 which one of the following sequences satisfies \(\rm DFT\;\left( {DFT\left\{ {x\left[ n \right]} \right\}} \right) = x\left[ n \right]\)
A.	x [n] = [1, 2, 3, 4]
B.	x [n] = [1, 2, 3, 2]
C.	x [n] = [1, 3, 2, 2]
D.	x [n] = [1, 2, 2, 3]
Answer» C. x [n] = [1, 3, 2, 2]