MCQOPTIONS
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| 1. |
The mean free path λ of a gas molecule as given by Maxwell is related to its diameter a, as |
| A. | \(\lambda = \frac{1}{{\sqrt {2mn{a^2}} }}\) |
| B. | \(\lambda = \frac{1}{\sqrt{2}n\pi a^2}\) |
| C. | \(\lambda = \frac{1}{{\sqrt {2\pi T{a^2}} }}\) |
| D. | \(\lambda = \frac{1}{{\sqrt {2\pi n{a^3}} }}\) |
| Answer» C. \(\lambda = \frac{1}{{\sqrt {2\pi T{a^2}} }}\) | |