The maximum values of the alternating voltage and current are 400 V and 20 A, respectively, in a circuit. The frequency of the alternating quantities is 50 Hz, and these quantities are sinusoidal. The phase angle of the current with respect to voltage is θ. Choose the correct expression for the voltage and current with respect to time t

Question

TuteeHUB · Accepted Answer

$v(t) = \frac{400}{\sqrt{2}} sin(100πt) V, i(t) = \frac{20}{\sqrt{2}} sin((100 + θπ )t) A$

TuteeHUB · Answer

v(t) = 400sin(100πt) V, i(t) = 20 sin(100πt) A

TuteeHUB · Answer

v(t) = 400sin(100πt) V, i(t) = 20 sin(100πt + θ) A

TuteeHUB · Answer

$v(t) = \frac{400}{\sqrt{2}} sin(100πt) V, i(t) = \frac{20}{\sqrt{2}} sin(100πt) A$

1.	The maximum values of the alternating voltage and current are 400 V and 20 A, respectively, in a circuit. The frequency of the alternating quantities is 50 Hz, and these quantities are sinusoidal. The phase angle of the current with respect to voltage is θ. Choose the correct expression for the voltage and current with respect to time t
A.	v(t) = 400sin(100πt) V, i(t) = 20 sin(100πt) A
B.	v(t) = 400sin(100πt) V, i(t) = 20 sin(100πt + θ) A
C.	\(v(t) = \frac{400}{\sqrt{2}} sin(100πt) V, i(t) = \frac{20}{\sqrt{2}} sin((100 + θπ )t) A\)
D.	\(v(t) = \frac{400}{\sqrt{2}} sin(100πt) V, i(t) = \frac{20}{\sqrt{2}} sin(100πt) A\)
Answer» C. \(v(t) = \frac{400}{\sqrt{2}} sin(100πt) V, i(t) = \frac{20}{\sqrt{2}} sin((100 + θπ )t) A\)

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