The Laplace transform of a signal x(t) is\(\frac{{4s + 1}}{{{s^2} + 6s + 3}}\) Determine the initial value x(0).

The Laplace transform of a signal x(t) is\(\frac{{4s + 1}}{{{s^2} + 6s

1.	The Laplace transform of a signal x(t) is\(\frac{{4s + 1}}{{{s^2} + 6s + 3}}\) Determine the initial value x(0).
A.	1/3
B.	4
C.	1/6
D.	4/3
Answer» C. 1/6