The inverse Laplace transform of \(\frac{1}{{\left( {s + 1} \right)\left( {s - 2} \right)}}\) is

\(\frac{{{e^{2t}} + {e^t}}}{3}\)

\(\frac{{{e^{2t}} + {e^{-t}}}}{3}\)

\(\frac{{{e^{2t}} - {e^{-t}}}}{3}\)

The inverse Laplace transform of \(\frac{1}{{\left( {s + 1} \right)\l

1.	The inverse Laplace transform of \(\frac{1}{{\left( {s + 1} \right)\left( {s - 2} \right)}}\) is
A.	\(\frac{{{e^{2t}} + {e^t}}}{3}\)
B.	\(\frac{{{e^{2t}} + {e^{-t}}}}{3}\)
C.	\(\frac{{{e^{2t}} - {e^{-t}}}}{3}\)
D.	\({e^{ - 2t}} - {e^t}\)
Answer» D. \({e^{ - 2t}} - {e^t}\)