MCQOPTIONS
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| 1. |
The inverse Fourier transform of \(F\left( {jw} \right) = \mathop \smallint \limits_{ - \infty }^\infty exp\left( { - j\omega t} \right)f\left( t \right)dt\) is |
| A. | \(f\left( t \right) = \mathop \smallint \limits_{ - \infty }^\infty \exp \left( { + j\omega t} \right)f\left( {j\omega } \right)d\omega \) |
| B. | \(f\left( t \right) = \frac{1}{{2\pi }}\mathop \smallint \limits_{ - \infty }^\infty \exp \left( { + \phi \omega t} \right)f\left( { + j\omega } \right)d\omega \) |
| C. | \(f\left( t \right) = \frac{1}{{2\pi }}\mathop \smallint \limits_{ - \infty }^\infty \exp \left( { - j\omega t} \right)f\left( { + j\omega } \right)d\omega\) |
| D. | \(f\left( t \right) = \frac{1}{{2\pi }}\mathop \smallint \limits_{ - \infty }^\infty \exp \left( { - j\omega t} \right)f\left( { + j\omega } \right)d\omega \) |
| Answer» C. \(f\left( t \right) = \frac{1}{{2\pi }}\mathop \smallint \limits_{ - \infty }^\infty \exp \left( { - j\omega t} \right)f\left( { + j\omega } \right)d\omega\) | |